secant math problem(help plsssssssssss)

Question

Given  where ,  determine the related acute angle and all possible principal angles to the nearest degree.  

Answer 1

SecT = -1.25 = - 5/4

CosT = 1/SecT = -4/5

T = about 180-36.9 = 143.1 degrees

angles with negative cosines are all in either quadrant II or III, with no acute angles. acute means less than 90 degrees.

maybe you want about 37 degrees = the reference angle which is acute

that reference angle also is in quadrants II, III, and IV

with angles 180-37= 143 degrees

180+37 = 217 degrees

and 360-37= 323 degrees

so,

37, 143, 217, 323 degrees