Find all of the real and imaginary roots (zero) of each function.

Question

y=3x^2+17x-2

Answer 1

f(x) = 3x^2 +17x -2

use the quadratic formula,

there are two real solutions since the discriminant is positive

x=-b/2a + or - (1/2a)sqr(b^2- 4ac)

x= -17/6 + or - (1/6)sqr(17^2 -(4)(3)(-2))

x=-17/6 +/- (1/6)sqr(313)

x=-17/6 +/- (1/6)17.6918

x=-17/6 +17.6918/6 or -17/6 - 17.6918/6

x= -34.6918/6 or 0.6918/6

x=about -5.7820 or 0.1153