The length of a given rectangle is 2 less than 4 times the width of the rectangle. Its perimeter is 51. What is its area?

Question

The length of a given rectangle is 2 less than 4

times the width of the rectangle. Its perimeter is

51. What is its area?

Answer 1

L=4W-2

2L+2W = 51

2(4W-2) +2W = 51

8W-4 +2W = 51

10W = 51+4 = 55

W = 55/10 = 5.5

:L = 4W-2 = 4(5.5)-2 = 22-2 = 20

Area = WL = 20(5.5) = 110