In the reaction represented by the equation 2Al2O3 ® 4Al + 3O2, calculate the theoretical amount in grams of oxygen, O2 produced if 17.93 grams Al2O3 decomposes? Show your work

Answer 1

2Al₂O₃ ==> 4Al + 3O₂ ...BALANCED EQUATION

molar mass 2Al₂O₃ = 101.96 g / mol

molar mass O₂ = 32.0 g / mol

moles 2Al₂O₃ present = 17.93 g x 1 mol / 101.96 g = 0.1759 mols 2Al₂O₃

Theoretical mass of O₂ = 0.1759 mols Al2O3 x 3 mol O₂ / 2 mol Al2O3 x 32.0 g O₂ / mol = 8.441 g O₂