
Mark M. answered 07/21/22
Mathematics Teacher - NCLB Highly Qualified
(t + 20)(N - 40) = 1300
N - 40 = 1300 / (t + 20)
N = [1300 / (t + 20)] + 40
(t + 20)(N - 40) = 1300, set t = 0, solve for N
(t + 20)(N - 40) = 1300, set t = 20, solve for N
(t + 20)(N - 40) = 1300, N = 50, solve for t
You do the graph.