perpendicular to the line y=6x+11 and passes through the point (-12, 3)

Question

Write the equation of the line, in Standard Form, with the given information

Answer 1

Perpendicular lines have a negative reciprocal of your original slope.

So looking at the problem in terms of y=mx+b, your original slope is 6, so the negative reciprocal is -1/6.

Now we use the point slope form of y-y₁=m(x-x₁) Now we plug our numbers in ans simplify to standard form.

y-3=(-1/6)(x- (-12))

y-3=(-1/6 x) - 2

y = (-1/6 x) + 1