I have a word problem that I need help with.

Question

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $35 and same-day tickets cost $25. For one performance, there were 55 tickets sold in all, and the total amount paid for them was $1725. How many tickets of each type were sold?

Answer 1

S = no. same-day tickets @ $25 ea; A = no. advance tickets @ $35 ea.

Need two equations because there are two unknowns.

One equation is for no. of tickets: A + S = 55

Other is for $'s: 35A + 25S = 1725

Best is to use substitution method: A = 55 - S

So new equation is 35(55 - S) + 25S = 1725.

You should be able to solve for S and use that result in the first equation to find A.