In 1991, the moose population in a park was measured to be 4770. By 1996, the population was measured again to be 5670. If the population continues to change linearly:

Question

A.) Find a formula for the moose population, P, in terms of t, the years since 1990.

P(t) = ____________

B.) What does your model predict the moose population to be in 2008?

___________

Answer 1

in 2008, 7,830 moose with linear growth given 4770 in year zero (1991) and 5670 in year five (1996)

simplest equation: y=180t + 4770

but you want a slightly more compllicated equation by making zero year 1990 instead of 1991.

so that shifts the t value right one unit on the graph

y= 180(t-1) +4770

y = 180t +4590

y = 180t + 4590

y=180(1) +4590 = 4770

y=180(6) + 4590 = 5670

y=180(18) + 4590 = 7830