Andrea B. answered 07/14/22
A=P(1+r/n)^nt
Given the information provided, P=5000, r=.07 (Change 7% to a decimal), n=1 (annually), t=20 (time in years)
So you are trying to solve for A to determine how much money is in the account after 20 years.
A=5000(1+.07/1)^1*20
A=5000(1.07)^20
A=5000(3.86968446)
A=19348.422
If you think about like they are taking $5000 and multiplying by 1.07 (adding 7%) each year, this answer makes sense.
At the end of year 1 there is 5350. Year 2 would be 5350*1.07=5724.50, year 3 ends with 6125.22. If you continued multiplying the previous answer by 1.07, you should end up with $19,348.42.