Sun K.

asked • 03/26/13

Find the flux of F over Q where Q is bounded?

Find the flux of F over Q where Q is bounded by z=sqrt(x^2+y^2), x^2+y^2=1 and z=0, F=<y^2, x^2*z, z^2>. (Answer: pi/2)

The divergence of the vector field is 2z, which is what I've found. And I know that x^2+y^2=r^2, z=r, r=0, x^2+y^2=0, how should I find the points of the integral and set up for the integral?

Sun K.

Thank you so much! Wow, you attended MIT? Did you know that MIT is my dream school? I'll apply there this fall after taking the SAT. But I don't have any extracurricular activities, can I still get accepted to MIT? I have some big reasons to go there, though.

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03/27/13

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