Find an equation of the line that

Question

Find an equation of the line that (a) has y-intercept of 11 and (b) is parallel to the line −1x+5y=6-1x+5y=6.

Write your answer in the form y=mx+by=mx+b.

Answer 1

-x + 5y = 6

slope of equation in form ax + by = c is -a/b

here a = -1 and b = 5, so slope = -(-1/5) = 1/5

line parallel to that has the same slope (m)

y-intercept of 11 means b = 11.

so equation of line in y= mx+ b form is y = (1/5)x + 11