
Mark M. answered 07/06/22
Mathematics Teacher - NCLB Highly Qualified
The first bounce is 32.5', (2)(25)(0.65)
a1 = 32.5
r = 0.65
S = a1 / (1 - r)
Total distance is 25 + S
Kore C.
asked 07/06/22A ball drops from a height of 25 feet. Each time it hits the ground, it bounces
up 65 percents of the height it falls. Assume it goes on forever, find the total
distance it travels.
Mark M. answered 07/06/22
Mathematics Teacher - NCLB Highly Qualified
The first bounce is 32.5', (2)(25)(0.65)
a1 = 32.5
r = 0.65
S = a1 / (1 - r)
Total distance is 25 + S
The simple answer is that it's a geometric sequence. The sum can be found like so:
25*[1+.65 + 652 +.653 +.654 +.655 +...] the down portion, plus
25*[.65 + .652 +.653 +.654 +.655 +...] the up portion
---------------------------------------------
25 + 50*[.65 + .652 +.653 +.654 +.655 +...]
25 + 50*(.65/(1-.65))
≅ 117.9 feet
But it's all so much more interesting than that! I will post an animation of this result momentarily.
edit: here is the animation: https://drive.google.com/file/d/1mgPSJR8Yjt4aIvicEfGojIv4Mkdi0v5h/view?usp=sharing
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Patrick F.
07/06/22