Let h(x)=(x+2)/(x-5). What is equivalent to h(h(x))?

Answer 1

h(x) = (x+2)/(x-5)

h(h(x)) = [(x+2)/(x-5) +2]/[(x+2)/(x-5) -5]

= (3x-8)/(27-4x)

BUT if by chance you meant to write either

h^-1(h(x)) or h(h^-1(x))

then the answer is just x

the composite of inverse functions just brings you back to where you started, x