J.R. S. answered • 06/29/22
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
copper(II) nitrate pentahydrate = Cu(NO3)2 ∗ 5H2O
Molar mass = 277.67 g / mol
mols Cu(NO3)2 ∗ 5H2O = 232.29 mg x 1 g / 1000 mg x 1 mol / 277.67 g = 8.36569x10-4 mols
Since each mol of Cu(NO3)2 ∗ 5H2O contains 1 mole of Cu2+, there are 8.36569x10-4 mols of Cu2+
Grams of Cu2+ = 8.36569x10-4 mols Cu2+ x 63.55 g / mol = 0.053164 g of Cu2+
This is in 1.45 kg of water or 1450 g of water.
Parts per million (ppm) can be defined as 1 g in 1 million g
0.053164 g of Cu2+ / 1450 g H2O x 106 g = 367 g Cu2+/106 g water = 367 ppm
(be sure to check the math)
J.R. S.
07/01/22
Jena A.
I divided by the molar mass of Copper nitrate by the molar mass of Cu2+ like this 232.29 mg *(63.55/187.56) = 78.706 mg Cu2+. Then take ratios of 78.706 mg Cu2+/1.45 kg W * 1 g/1000mg * 1 kg/ g = 54.28 ppm. Thats the approach I did.07/02/22
J.R. S.
07/02/22
Jena A.
I checked the math and got 54.28 ppm. I don't know if this is correct07/01/22