How do you write an equation in standard form of the lines that passes through (-3,2) and (6,-1)

Answer 1

(-3,2) and (6,-1) have a line through them with slope = (2+1)/(-3-6) = 3/-9 =-1/3

-1/3 = (y+1)/(x-6)

-1(x-6) = 3y +3

x +3y = 3

standard form for a linear equation is: Ax +By = C

in this example, A=1, B=3 and C= 3