slope intercept

Question

what is the slope intercept equation of the line that contains the point (-6, 3) and is parallel to the line passing through (2,3) and (-3, -8)

Answer 1

(2,3) and (-3,-8) have a line through them with slope = change in y values divided by corresponding change in x values = (3+8)/(2+3) = 11/5

a parallel line has the same slope 11/5

a parallel line though the point (-6, 3) is

(y-3)/(x+6) = 11/5 in point slope form

y-3 = (11/5)(x+6) = (11/5)x + 66/5

y = (11/5)x + 66/5 +3

y = (11/5)x + (66+15)/5

y = (11/5)x + 81/5 is the equation in slope intercept form. slope = the coefficient of the x term when the linear equation is solved for y. y intercept = 51/5 = the constant term

general equation is y=mx + b, where m=slope and b= y intercept

m= 11/5, b = 81/5 = 16.2

check the answer by pluggint in the point (-6,3) into the equation

3 = (11/5)(-6) + 81/5 = -66/5 + 81/5 = 15/5= 3