This a direct consequence of the Weierstrass M-test. Indeed, 1/[np + nq x2] ≤ 1/np for all x, and ∑[n = 1, ∞] 1/np < ∞ since p > 1. By the Weierstrass M-test, the series ∑[n=1, ∞] 1/[np + nq x2] converges uniformly on (-∞,∞).

Eugene E.
06/16/22
Ashley P.
asked 06/16/22How do we show that sigma(n=1 to infinity){ [1/[ np+ (nq*x2) )] } is uniformly convergent , where x not equal to 0 & when p>1
Types of tests that can be used: Weierstrass M-test, Cauchy Criterion for uniform convergence, Mn test etc.
This a direct consequence of the Weierstrass M-test. Indeed, 1/[np + nq x2] ≤ 1/np for all x, and ∑[n = 1, ∞] 1/np < ∞ since p > 1. By the Weierstrass M-test, the series ∑[n=1, ∞] 1/[np + nq x2] converges uniformly on (-∞,∞).
Eugene E.
06/16/22
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Ashley P.
Here, they specify x is not equal to 0. So, can we take the equality in 1/[np + nq x2] ≤ 1/np ?06/16/22