Math help with homework

Question

A rectangle has a length of 11 feet less than 9 times its width. If the area of the rectangle is 5798 square feet, find the length of the rectangle

Answer 1

L = 9W-11

A =5,798 = LW = (9W-11)W = 9W^2 -11W

9W^2 - 11W -5798 = 0

use the quadratic formula

W = 11/18 + or - (1/18)sqr(121 +36(5798))

W = (11+ or - 457)/18 = 468/18= 26 feet wide

L = 9(26)-11= 234-11 = 223 feet long