Raymond B. answered 06/11/22
Math, microeconomics or criminal justice
Probability of at least 4 hits = 1 - Probability of 0,1,2 or 3 hits
1-P(<4) = 1 - (P(0) + P(1) + P(2) + P(3))
1-Pr(<4) = 1- [34C0(.758)^34 + 34C1(.758)^33(.242) + 34C2(.758)^32(.242)^2 + 34C3(.758)^31(.242)^3]
nCr = n!/(n-r)!r! 34C0 = 1, 34C1 = 34, 34C2 = 34!/32!2! = 17(33)= 561, 34C3 = 34!/31!3! = 17(11)32=5984
but maybe you meant probability of exactly 4 hits, not any more or less than 4, then
P(4) = 34C4(.758)^30(.242)^4 = 34!/30!4!(.758)^30(.242)^4 = [34(33)(32)(31)/4(3)(2)](.758)^30(.242)^4
P(4) = 17(11)(8)(31)(.758)^30(.242)^4
P(4) = 46376(.758)^30(.242)^4
P(4) = 11.38595482(.242)^4
P(4) = 0.039050888
P(exactly 4 hits in 32 at bats) = about 3.91%