Gotcha! Let's do this using elimination and substitution. Elimination: So we have to artificially multiply 3 with
y = -x-2 to cancel out our x. This will give you -3x-6
Now we have the following:
-3x-6
3x+2
---------- (add)
We get: y = -4
Plug in Y= -4 into any of the equations to solve for x.
Ex: -4 = 3x+2
X = -2
Thus one possible solution to this system of equations is: (-2, -4)
We can check if this solution is TRUE or not by simply plugging our points back into the equations.
Y=-x-2
Y=3x+2
-4 = - (-2) -2
-4 = 0 This is FALSE. Thus, we cannot solve this system of equations by elimination.
Lets try using substitution: 3x+2 = -x-2
4x = -4
x = -1
Let's find y: I'll plug the x value into any given equation.
y = 3(-1) +2
y = -3 +2 = -1
or
y = - ( - 1 ) - 2
See, we get the same y value regardless of where we plug in the x value.
y = -1
Let's verify if our solution is TRUE.
(-1,-1)
y = 3x+2
-1 = 3(-1) +2
-1 = -1 TRUE
y = -x-2
- 1 = - ( - 1 ) - 2
-1 = -1 TRUE
ANS: For that reason, substitution works, and our solution is (-1,-1) You can also verify this graphically using DESMOS online calculator or a graphing calculator. You will notice that (-1,-1) is the point of intersection of both equations. I hope this helps! :)
Jayla L.
Yes, this was lots of help. Thank you for helping.06/11/22