Basic mathematics

Question

h(x) = 5x-1/1

Find h^-1(x)

Answer 1

h(x) 5x-1/1 = 5x-1

h^-1 = (x+1)/5

switch x and y and solve for the new y

y=5x-1

x =5y-1

5y = x+1

y = (x+1)/5

y = h^-1(x) = (x+1)/5

if (x,y) is on the graph of h(x), then (y,x) is on the graph of its inverse

(0,-1) is on the graph of h(x)

(-1,0) is on the graph of h^-1(x)

h(x) subtracts 1 h^-1(x) adds 1

h(x) multiplies by 5, h^-1(x) divides by 5

the inverse function has reverse arithmetic operations