Latoya must choose a number between 49 and 95 that is a multiple of , 4, 7and 14. Write all the numbers that she could choose.

Answer 1

56, 63, 70, 77, 84, 91 are divisible by 7

eliminate odd numbers leaving

56, 70 and 84

70 isn't divisible by 4, leaving

56 and 84

56 and 84 are divisible by 4, 7 and 14

56= 7x2x4=14x4

84 = 7x2x2x3=14x6=4x7x3

56/4 =14

56/7 = 8

56/14 = 4

84/7 = 12

84/4 = 21

84/14= 6