Hi Candi,
x2 + 12x = 13 --- Given equation
x2 + 6x + 6x = 13 --- 12x = 2 (6x) = 6x + 6x
x2 + 6x + 6x + 62 = 13 + 62 --- Add 62 on both sides to complete the square
x2 + 6x + 6x + 62 = 72 --- 13 + 62 = 13 + 36 = 49 = 72
x(x + 6) + 6(x + 6) = 72
(x + 6) (x + 6) = 72
(x + 6)2 = 72
x + 6 = ± 7
x + 6 = 7 or x + 6 = - 7
-6 -6 -6 - 6 --- Subtract 6 on both sides
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x = 1 x = - 13
So , x = 1 , -13 are the solutions for the given equation.
Hope this helps!