Solve the given system by substitution.

Question

Answer 1

-3b = 4b/3 - 13

-9b/3 = 4b/3 - 13

0 = 4b/3 + 9b/3 - 13

13 = 4b/3 +9b/3

13 = 13b/3

39 = 13b

3 = b

c = -3(3)

c = -9

Answer 2

-3b = 4b/3 - 13

4b/3 + 9/3 = 13

13b/3 = 13

b = (3/13)(-3) = 3

b=3

c=-3b = -3(3) = -9

c= -9, b=3

(b,c) = (3,-9)