Raymond B. answered 05/31/22
Math, microeconomics or criminal justice
(x-1)^2 + [(y-2)^2]/9= 1
or
9(x-1)^2 + (y-2)^2 = 9
or
9(x^2-2x +1) + y^2-4y +4 = 9
9x^2 -18x +9 + y^2 -4y +4 = 9
9x^2 -18x + y^2 -4y = -4
what you probably want is
(x-1)^2 + [(y-3)^2)/3^2 = 1
where (1,3) is the center of the ellipse and a=1, b= 3, the semi axes
5--1 =6 6/2 = 3 is the y coordinate of the center of the ellipse
1--1= 2. 2/2 = 1 is the x coordinate of the ellipse center