what is the possible measures of the third side of 11 and 20, 12 in inequality

Answer 1

if 11 and 20 are 2 sides of a right triangle

the 3rd side is either the hypotenuse = sqr(11^2 + 20^2) = sqr(121+400) = sqr521 = about 22.8

which is a triangle with Area = 11(20)/2 = 110

or 20 is the hypotenuse and the 3rd side is sqr(20^2-11^2) = sqr(400-121) = sqr279 = about 16.7

which is a triangle with Area = 16.7(11)/2 = about 91.9

but the phrase: "12 in inequality" is confusing. Maybe it refers to 12 inches in a foot? so the possibilities are 22.8 feet or 16.7 feet for the 3rd side?

even then, the "inequality" part isn't clear. the longest side of any triangle, right or otherwise, must be less than the sum of the other two sides. Maybe the 3rd side is 12 less than the sum of the other two sides? 20+11-12 = 19 as the largest possible 3rd side? a 20-11-19 triangle is not a right triangle. but nothing really suggests it is a right triangle, or even a triangle. The 3rd side can't be greater than the sum of the other 2 sides, and it can't be less than the difference of the other 2 sides, so the 3rd side would also have to be more than 20-11 = 9. that means the 3rd side = s is between 9 and 19: 9<s<19

sometimes the major problem is figuring out what the problem is