In terms of a formula: ni = MiV or moles = molarity * volume
This gives you the moles of solute, not the moles of a particular ion. These salts dissociate completely, so the moles of a particular ion per more of formula unit is just the subscript of the ion:
There is a little bit of a problem with the question in that these solutions are not actually mixed together in any proportion. We have to make the assumptions that we added enough solid salts to some water to reach the molarity of the salt given we added enough water at the end to get 1 liter of solution.
1 liter (.1 moles NaCl/ 1 liter) (1 mole Na+/mole NaCl) = .1 moles Na+
1liter(3.0 moles Na2SO4/ 1 liter) (2 moles Na+/mole of Na2SO4) = 6 moles Na+
I'll leave the last one for you. Then add up the moles of Na+ contributed by each salt.