Asok B. answered 03/25/13
Ph. D in Biochemistry, willing to teach Chemistry, Biochemistry, Math
If 'h' is the height of the building, and X is the distance, then h/x = tan 35
therefore, x/h= 1/tan35 .....(1)
When he moves 100 feet toward the building the angle changes to 400
so h/x-100 = tan 40
therefore ( x-100) /h = 1/tan 40
So x/h-100/h = 1/tan40 ....(2)
Subtracting (2) from (1) we get 100/h = 1/tan35-1/tan40
therefore, h = 100 (tan40. tan35) /(tan 40- tan35)