Raymond B. answered 05/22/22
Math, microeconomics or criminal justice
F= 22+S
(F+S)5 = 860
(22+S +S) = 860/5
2S = 172-22
S = 150/2 = 75 mph = Slower Train's speed
F = 30+22 = 97 mph = Faster Train's speed
(97+75)(5) = 860
172(5) = 860
speed times time = distance
(of course, after "meeting" coming at each other at those speeds, their speeds drop to zero each, as they destroy and derail each other. Or if not, then at best, the faster train drops to 11 mph and the slower to negative 11 mph as the faster pushes the slower down the rails, still with a 22 mph difference.)