Help with math please

Question

the braking distance of a car varies directly as the square of the speed of that car. Assume that a car traveling 35 miles per hour can stop 43 feet after the brakes are applied. how long is the braking distance for the same care traveling at 65

Answer 1

B=kS^2

43=k(35^2) =1225k

k = 43/1225

B=43/1225)S^2

B= (43/1225)(65^2)

B= 43(65^2)/35^2

B =43(13^2)/7^2

B=43(169)/49

B= 148.3061224 feet = braking distance when speed=65 mph

B= about 148 feet