If you have a bag with 5 snickers and 4 twix. What is the probability of pulling a snickers and then another snickers, if you don’t replace the initial snickers.

Answer 1

(5/(5+4)(4/4+4)

= (5/9)(1/2)

= 5/18

= 0.2777...

= 27.77..%

= about 27.8% chance of getting 2 snickers in a row

5/9 on the first pull = 55.55...%

then 1/2 chance on the 2nd pull = .50 %

1/2 of 55.55= 55.55.../2 = 27.777%