Write the standard form of the equation of a circle that contains the point (10,8) and has center (0,0)

Answer 1

(10)^2 + (8)^2 = r^2 = 164

x^2 + y^2 = 164 is the equation of a circle with center at the origin and through the point (10,8)

any equation of a circle centered at the origin has the form x^2 +y^2 = r^2 replace x by 10 and y by 8 and solve for r^2

another method is find

the distance from the point (10,8) to (0,0)

use the Pythagorean Theorem

r^2 = 10^2 + 8^2 = 100+64 = 164

x^2+y^2 = r^2 = 164