Raymond B. answered 05/13/22
Math, microeconomics or criminal justice
f(x) = (x-3)(x-8)(x-9)
= (x^2 -11x +24)(x-9)
= x^3 -20x^2 +123x - 216
f'(x) = 3x^2 -40x -123
f'(c) = 0 = 3c^2 -40c -123
c = 4/6 + or - (1/6)sqr(1600-4(3)(123))
c = about 4.81 and 8.52
c = 4.81, 8.52
or
c= 4.8, 8.5 rounded off to once decimal place
f(x) has 3 x intercepts, 3, 8, and 9
f(x) = 0 when x=3,8 or 9
f'(x) = 0 once between 3 and 8, and once between 8 and 9
f(x) has a relative maximum at x = about 4.81
f(x) has a relative minimum at x= about 8.52