Raymond B. answered 05/12/22
Math, microeconomics or criminal justice
20/4=5
maximum area = 5^2 = 25
Length = 5
Width = 5
a square has maximum area for a quadrilateral of fixed perimeter
A = LW
2L + 2W = 20
L+W = 10
L= 10-W
or solve with a little calculus
A = (10-W)W = 10W -W^2
take the derivative and set =0
A' = 10 -2W =0
2W = 10
W =10/2 = 5 = Width
L=10-W = 10-5 = 5 = Length
Maximum Area = 5 x 5 = 25