Peter R. answered 05/12/22
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
The only way that all the criteria can be met is if the time is 1 hour.
Car A goes 30 mi in 1 hr = 30 mph
Car B goes 25 mi in 1 hr = 25 mph , or 5 mph slower, as specified.
If "t" was 2 hrs it wouldn't work out.
Car A goes 30 mi in 2 hrs = 15 mph
Car B goes 25 mi in 2 hrs = 12.5 mph (not a difference of 5 mph)
Can also use algebra: A's rate is rA = 30/t mph; B's rate is rB = 25/t mph, but rB = rA - 5.
So 25/t = 30/t - 5. Mult both sides by t. 25 = 30 - 5t -> -5t = 25 - 30 -> -5t = -5, so t must = 1 hr.and B's rate is 25 mph (answer is C)