Raymond B. answered 05/11/22
Math, microeconomics or criminal justice
row 1 has 20 seats
row 2 has 24 seats
row 3 has 28 seats
row n has 20+4(n-1)
row 29 has 20+4(28) = 20+ 112 = 132 seats
sum of the arithmetic sequence,with n=29, a1 =20, a29 = 132
is S29 = (n/2)(a1 +a29)
= 29/2)(20+132)
= 29/2)(152)
= 29(76)
= 2204 total seats
sum of an arithmetic sequence = half the number of terms times (the first term plus the last term)