how many liters of a 10% alcohol solution must be mixed with 50 liters of a 90% solution to get a 50% solution

Answer 1

50 liters of 10% mixed with 50 liters of 90% = 100 liters of 50%

.9(50) + .1(x) = .5(50+x)

45 +.1x = 25 +.5x

.5x -.1x = 45 -25

.4x = 20

x =20/.4 = 50 Liters of 10%

10 is within 40 of 50

90 is within 40 of 50

equal amounts of 10 and 90 will yield 50