the rate of change for f(x) on the interval of [0, 2]?

Answer 1

We know that

The formula for average rate of change is: f(b)−f(a)/ b−a Given,a=0 and b=2.

Put these value in above formula:

Average rate of change = f(2)−f(0)/2-0=f(2)-f(0)/2

For example:

x^3−3x^2+7x−1 over the interval [0, 2]

a=0 b=2

f(0)=0^3−3(0)^2+7(0)−1=0-0+0-1=-1

f(2)= (2)^3-3(2)^2+7(2)-1= 8-12+14-1=9

Average Rate of change= 9-(-1)/2=10/2=5

The average rate of change over the interval [0, 2] is 5.

If you like the way I have answered this question, then please leave a comment and send me a message letting me know you liked it ! You can take a look at over other problems I have solved here on Wyzant Ask an Expert using the link on my tutor page. Please contact me about setting up an online session to help you achieve your best potential test scores and grades in Mathematics, Statistics, and Physics.