A poster has a perimeter of 10 feet and an area of 6 square feet. What are the dimensions of the poster?

Answer 1

3 feet by 2 feet

Area =3(2) = 6 ft^2

Perimeter = 2(3+2) = 2(5) = 10 feet

A = LW = 6

L =6/W

P =2(L+W)=10

L+W= 10/2 = 5

6/W + W = 5

6+ W^2 = 5W

W^2 -5W + 6 =0

(W-3)(W-2) = 0

W =2 or 3 feet wide

L =6/W = 6/2 or 6/3 = 3 or 2 feet long

dimensions are 2 feet by 3 feet