Use ordinary division of polynomials to find the quotient and remainder.

Question

(b²-3b-40)÷(b+3)

Answer 1

quotient = b-6 with remainder of -22

b-6 times b+3 = b^2 -3b -18

18-40 = -22

-3| 1 -3 -40

1 -3

-6 18

-22

b -6 plus remainder -22