Aden Z. answered 05/05/22
VT Admit for Math levels Algebra 2 and below
To simplify imagine 2 questions first
The answers for those questions could be:
a-a a-b a-c a-d
b-a b-b b-c b-d
c-a c-b c-c c-d
d-a d-b d-c d-d
So for 2 questions with four choices you get 4^2 = 16
12 different questions.
4^12
16,777,216 C.