If n is not zero, and (xy)^(n)=1, express x^(n –1) as a power of y^(3).

Answer 1

(xy)^n = 1

x^n = 1/y^n

x^(n-1) = x^n/x= 1/xy^n

x^(3-1) = 1/xy^3

x^2 = 1/xy^3

x^3 = 1/y^3

x = cube root of 1/y^3

x = 1/y

y = 1/x

graphically it's a rectangular hyperbola with vertices (1,1) and (-1,-1) vertical asymptote x=0, horizontal asymptote y= 0. the axes are the asymptotes