An arrow is shot vertically upward from a platform 35ft high at a rate of 219ft/sec. When will the arrow hit the ground? Use the formula: h=−16t2+v0t+h0. (Round your answer to the nearest tenth.)

Answer 1

h = -16t^2 + 219t + 35 =0

use the quadrtic formula

h = -b/2a + (1/2a)sqr(b^2 -4ac) where a =-16, b=219, c=35

t = 219/32 + (1/32)sqr(219^2 +4(16)(35))

t = about 6.84 + 7

t = about 13.8 seconds to reach the ground