Word problems24

Question

There consecutive numbers such that 9 times the first number equals the third number plus 7 times the second number

Answer 1

9 times the 1st = the 3rd pluse 7 times the 2nd

9x = x+2 +7(x+1)

Let x = 1st number,

x+1 = 2nd number

x+2 = 3rd number

9x = x+2 +7x +7

9x-x-7x =2+7

x =9

x+1=10

x+2 = 11

the 3 consecutive integers are 9,10 and 11

9(9) = 11 +7(10)

81 = 11+70