Dayv O. answered 04/28/22
Caring Super Enthusiastic Knowledgeable Calculus Tutor
right is that the transformation to spherical
transforms dxdydz to r2sin(a)drdθda,,,,,,where a is angle measured from z axis to line formed connecting origin to point. Note a will only go from pi/4 to 0. θ will go from 0 to pi/2, and r from 0 to 2.
V=∫∫∫r2drdθsinada,
=∫∫(√2/2)r2drdθ,,,,,,integral of sinada = -cosa
=∫(pi/2)(√2/2)r2dr
=(8/3)(pi/2)(√2/2)
=(2pi√2)/3