Daniel B. answered 04/27/22
A retired computer professional to teach math, physics
It is not continuous at (0,0) because the lim(f(x,y)) as x,y-> 0 does not even exist.
Pick any constant k and approach (0,0) along the curve y = kx.
On that curve
f(x,y) = kx²/(x² + (kx)²) = k/(1 + k²)
For each different values of k the limit is different.