
Yefim S. answered 04/27/22
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f(7,2 ) = ln(7 - 6) = 0
∂f/∂x = 1/(x - 3y); ∂f/dy = - 3/(x -3y). At (7, 2) ∂f/∂x = 1; ∂f/∂y = - 3
Linear approximation L(x,y) = 0 + 1(x - 0) - 3(y - 0) = x - 3y
L(x, y) = x - 3y