(3) (y + 5) is less than or equal to 36
multiplying gives 3y + 15 is less than or equal to 36.
Then 3y is less than or equal to 36 - 15, so 3y is less than or equal to 21.
Divide both sides of the equation by 3, gives y is less than or equal to 7.
Natalie R.
asked 04/25/22Three times the sum of a number,Y, and 5 is at most 36. Write inequality and solve Y.
(3) (y + 5) is less than or equal to 36
multiplying gives 3y + 15 is less than or equal to 36.
Then 3y is less than or equal to 36 - 15, so 3y is less than or equal to 21.
Divide both sides of the equation by 3, gives y is less than or equal to 7.
3(y+5)≤36 is the required inequality.
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