
Yefim S. answered 04/23/22
Math Tutor with Experience
Equation of 1st circle is r = 2; equation of second circle is r = 2cosθ;
Mass m = ∫∫Rydxdy. Regioon R in polar system: {2cosθ ≤ r ≤ 2; 0 ≤ θ ≤ π/2}; y = rsinθ; dxdy = rdrdθ;
m = ∫0π/2∫2cosθ2r2sinθdrdθ = ∫0π/2r3/32cosθ2sinθdθ = 1/3∫0π/2(8 - 8cos3θ)sinθdθ = 8/3(- cosθ + cos4θ/4)0π/2 =
= 8/3(1 - 1/4) = 8/3·3/4 = 2