Daniel B. answered 04/23/22
A retired computer professional to teach math, physics
It is not continuous because lim(f(x,y)) as (x,y)->(0,0) is not equal 1.
(Actually the limit does not even exist.)
To see that the limit cannot be equal 1, considering approaching (0,0)
along the curve
y = x1/3
On that curve, f becomes a function of the single variable x
f(x) = (xsin³x1/3)/(x²+(x1/3)6) =
(xsin³x1/3)/(2x²) =
(sin³x1/3)/(2x)
As x->0, lim(f(x)) = ∞